X^2+49x=420

Solution for X^2+49x=420 equation:

X^2+49X=420

We move all terms to the left:

X^2+49X-(420)=0

a = 1; b = 49; c = -420;
Δ = b2-4ac
Δ = 492-4·1·(-420)
Δ = 4081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{4081}}{2*1}=\frac{-49-\sqrt{4081}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{4081}}{2*1}=\frac{-49+\sqrt{4081}}{2}
$